Class 10 · Maths · Coordinate Geometry

Distance, section formula, area of triangle MCQs

Practice Distance, section formula, area of triangle multiple-choice questions from Coordinate Geometry (Class 10 Maths) - tap an answer for instant feedback and a step-by-step solution. Practice the full set free on the RankByte app.

Distance, section formula, area of triangleQuiz - Solve & Score

  1. Q1. On a treasure map ruled in metre squares a chest sits at (-1, -8) while an old well lies at (1, -3); what straight-line distance separates them?

    • A.7
    • B.29
    • C.sqrt(29)
    • D.sqrt(21)

    Answer: C. sqrt(29)

    Distance = sqrt((x2-x1)^2+(y2-y1)^2) = sqrt((2)^2+(5)^2) = sqrt(4+25) = sqrt(29) = sqrt(29).

  2. Q2. A vacuum robot parked at (3, 8) on a floor plan in metres glides directly to a spill at (5, -3); what is the length of its diagonal route?

    • A.13
    • B.5*sqrt(5)
    • C.125
    • D.3*sqrt(13)

    Answer: B. 5*sqrt(5)

    Distance = sqrt((x2-x1)^2+(y2-y1)^2) = sqrt((2)^2+(-11)^2) = sqrt(4+121) = sqrt(125) = 5*sqrt(5).

  3. Q3. Two phone towers are plotted on an engineer's km grid at (-5, 6) and (0, 4); what is the gap between the towers?

    • A.sqrt(21)
    • B.sqrt(29)
    • C.7
    • D.29

    Answer: B. sqrt(29)

    Distance = sqrt((x2-x1)^2+(y2-y1)^2) = sqrt((5)^2+(-2)^2) = sqrt(25+4) = sqrt(29) = sqrt(29).

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