Trigonometric ratios of complementary angles MCQs
Practice Trigonometric ratios of complementary angles multiple-choice questions from Introduction to Trigonometry (Class 10 Maths) - tap an answer for instant feedback and a step-by-step solution. Practice the full set free on the RankByte app.
Trigonometric ratios of complementary anglesQuiz - Solve & Score
Q1. Evaluate (use sin(90-x)=cos x etc.): sin 12 / cos 78
- A.0
- B.3
- C.1
- D.2
Answer: C. 1
Q2. The value of tan 12 . cot 12 is:
- A.3
- B.0
- C.2
- D.1
Answer: D. 1
Given 12, 12, asked for the unknown. By recall that in a right triangle with legs p, b and hypotenuse h: sin = p/h, cos = b/h, tan = p/b. so the answer = 1. identify the side-pair demanded and read off the ratio. Therefore option D) 1. Others fail: option A) '3' fails since Wrong: a common multi-step slip gives this; option B) '0' is wrong because Wrong: uses an incorrect intermediate value.
Q3. Evaluate (use sin(90-x)=cos x etc.): sin 12 . sec 78
- A.0
- B.3
- C.1
- D.2
Answer: C. 1
Given 90, 12, 78, asked for Evaluate (use sin(90-x)=cos x etc. By use complementary-angle identities sin(90-x)=cos x, cos(90-x)=sin x, tan(90-x)=cot x. use complementary-angle identities sin(90-x)=cos x, cos(90-x)=sin x, tan(90-x)=cot x → the expression collapses via sin^2 + cos^2 = 1 or tan*cot = 1 → hence the value = 1. rewrite each term in the expression with this substitution. Consequently option C) 1. Others fail: option A) '0' misses the point - Wrong: uses an incorrect intermediate value; option B) '3' is wrong because Wrong: a common multi-step slip gives this.
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