Division algorithm for polynomialsPractice Questions & MCQs
Practice Division algorithm for polynomials questions from Polynomials (Class 10 Maths) - important MCQs with answers and step-by-step solutions. Solve the sample questions below, then practice the full set free on the RankByte app.
Division algorithm for polynomialsQuiz - Solve & Score
Q1. For what value of k is (x - 2) a factor of p(x) = x^3 + (-3)x^2 + k x + (-6)?
- A.-5
- B.-10
- C.10
- D.5
Answer: D. 5
Q2. For what value of k is (x - 1) a factor of p(x) = x^3 + (5)x^2 + k x + (-7)?
- A.1
- B.2
- C.0
- D.-1
Answer: A. 1
Q3. For what value of k is (x - 3) a factor of p(x) = x^3 + (-4)x^2 + k x + (-3)?
- A.4
- B.12
- C.-4
- D.-12
Answer: A. 4
Given 3, 3, -4, 2, -3, asked for the unknown. By apply the quadratic formula x = (-b +/- sqrt(b^2 - 4ac))/(2a) to the given equation. apply the quadratic formula x = (-b +/- sqrt(b^2 - 4ac))/(2a) to the given equation → so the required value = 4. substitute the coefficients and simplify. Thus option A) 4. Others fail: option B) '12' is wrong because Wrong: uses an incorrect intermediate value; option C) '-4' misses the point - Wrong: a common multi-step slip gives this.
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Get early accessDivision algorithm for polynomials - Frequently asked questions
Where can I practise Division algorithm for polynomials questions for Class 10 Maths?
RankByte has Division algorithm for polynomials practice questions and MCQs from Polynomials (Class 10 Maths), each with the correct answer and a step-by-step solution - free to start.
Are these Division algorithm for polynomials questions important for the exam?
Yes. These Division algorithm for polynomials important questions follow the Maths exam pattern (CBSE Boards, plus JEE and NEET foundation), so they help with both school and competitive prep.
Do the Division algorithm for polynomials questions come with answers and solutions?
Every Division algorithm for polynomials question on RankByte comes with the correct answer and a full step-by-step solution, so you learn the concept instead of just guessing.