Solution by factorisation MCQs
Practice Solution by factorisation multiple-choice questions from Quadratic Equations (Class 10 Maths) - tap an answer for instant feedback and a step-by-step solution. Practice the full set free on the RankByte app.
Solution by factorisationQuiz - Solve & Score
Q1. If the product of two consecutive odd positive integers is 99, the integers are (NCERT):
- A.7 and 9
- B.5 and 7
- C.11 and 13
- D.9 and 11
Answer: D. 9 and 11
Given 99, asked for the unknown. By recall that in a right triangle with legs p, b and hypotenuse h: sin = p/h, cos = b/h, tan = p/b. so the answer = 9 and 11. identify the side-pair demanded and read off the ratio. Putting it together option D) 9 and 11. Others fail: option A) '7 and 9' is incorrect: 9 x 11 = 99; option B) '5 and 7' fails since It is 9 and 11.
Q2. Two consecutive positive integers multiply to 30. Find the smaller one:
- A.4
- B.5
- C.30
- D.6
Answer: B. 5
Q3. If n(n+1) = 42, the value of n (positive) is:
- A.42
- B.7
- C.6
- D.5
Answer: C. 6
We are told that 1, 42 (math, chapter 'Quadratic Equations'). Our target: the unknown asked. This is a classic application of hence the required answer = 6. Substituting and simplifying: hence the required answer = 6. Set up the relation specified by the stem (formula / theorem from the relevant Class-10 chapter) and substitute the listed numerical data. Matching this against the options, C) 6 is the answer. As for the others, option A) '42' fails since Wrong: a common multi-step slip gives this; option B) '7' misses the point - Wrong: a step was skipped or HCF/LCM swapped.
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