Mean of grouped dataPractice Questions & MCQs
Practice Mean of grouped data questions from Statistics (Class 10 Maths) - important MCQs with answers and step-by-step solutions. Solve the sample questions below, then practice the full set free on the RankByte app.
Mean of grouped dataQuiz - Solve & Score
Q1. Which is true about the mean?
- A.it has the same units as the data
- B.it is squared units
- C.it is unit-less
- D.it is always a percentage
Answer: A. it has the same units as the data
NCERT fact (math, chapter 'Statistics'): Mean of a grouped distribution: x_bar = sum(f_i * x_i) / sum(f_i), using class-marks x_i (mid-points) and frequencies f_i; tabulate fx, then divide => the ratio simplifies to a single value; hence the mean = it has the same units as the data. Why option A fits - Correct. Distractor analysis: option B) 'it is squared units' is wrong because Same units as the observations; option C) 'it is unit-less' fails since It carries the data's units. Final answer - A) it has the same units as the data.
Q2. Find the mean of the grouped frequency data [0-10: 5, 10-20: 8, 20-30: 12, 30-40: 10, 40-50: 5]:
- A.30.5
- B.25.5
- C.25.83
- D.26.67
Answer: B. 25.5
Given 0, -10, 5, 10, -20, asked for Find the mean of the grouped frequency data [0-10: 5, 10-20: 8, 20-30: 12, 30-40: 10, 40-50: 5]. By mean of a grouped distribution: x_bar = sum(f_i * x_i) / sum(f_i), using class-marks x_i (mid-points) and frequencies f_i. hence the mean = 25.5. tabulate fx, then divide. Thus option B) 25.5. Others fail: option A) '30.5' is incorrect: Wrong: a common multi-step slip gives this; option C) '25.83' fails since Wrong: a step was skipped or HCF/LCM swapped.
Q3. Find the mean of the grouped frequency data [5-10: 4, 10-15: 7, 15-20: 11, 20-25: 9, 25-30: 4]:
- A.18.33
- B.22.79
- C.17.95
- D.17.79
Answer: D. 17.79
Given 5, -10, 4, 10, -15, asked for Find the mean of the grouped frequency data [5-10: 4, 10-15: 7, 15-20: 11, 20-25: 9, 25-30: 4]. By mean of a grouped distribution: x_bar = sum(f_i * x_i) / sum(f_i), using class-marks x_i (mid-points) and frequencies f_i. hence the mean = 17.79. tabulate fx, then divide. Consequently option D) 17.79. Others fail: option A) '18.33' misses the point - Wrong: uses an incorrect intermediate value; option B) '22.79' doesn't hold - Wrong: a common multi-step slip gives this.
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Yes. These Mean of grouped data important questions follow the Maths exam pattern (CBSE Boards, plus JEE and NEET foundation), so they help with both school and competitive prep.
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