Class 10 · Maths · Surface Areas and Volumes

Conversion of one solid into another MCQs

Practice Conversion of one solid into another multiple-choice questions from Surface Areas and Volumes (Class 10 Maths) - tap an answer for instant feedback and a step-by-step solution. Practice the full set free on the RankByte app.

Conversion of one solid into anotherQuiz - Solve & Score

  1. Q1. How many cones (radius 2 cm, height 4 cm) can be made by melting a sphere of radius 6 cm?

    • A.27
    • B.6
    • C.54
    • D.55

    Answer: C. 54

    Reading the problem, 2 cm, 4 cm, 6 cm (math, chapter 'Surface Areas and Volumes'). Our target: How many cones (radius 2 cm, height 4 cm) can be made by melting a sphere of radius 6 cm?. The principle that connects these is - hence the answer = 54. Substituting and simplifying: hence the answer = 54. Draw the relevant radii and use the fact that the tangent _|_ radius at the contact point. That lands on option C) 54. As for the others, option A) '27' is wrong because Wrong: uses an incorrect intermediate value; option B) '6' is wrong because Wrong: a common multi-step slip gives this.

  2. Q2. How many cones (radius 2 cm, height 9 cm) can be made by melting a sphere of radius 6 cm?

    • A.12
    • B.24
    • C.25
    • D.6

    Answer: B. 24

    Given 2 cm, 9 cm, 6 cm, asked for How many cones (radius 2 cm, height 9 cm) can be made by melting a sphere of radius 6 cm?. By hence the answer = 24. hence the answer = 24. draw the relevant radii and use the fact that the tangent _|_ radius at the contact point. Hence option B) 24. Others fail: option A) '12' doesn't hold - Wrong: uses an incorrect intermediate value; option C) '25' is wrong because Wrong: a step was skipped or HCF/LCM swapped.

  3. Q3. How many cones (radius 3 cm, height 6 cm) can be made by melting a sphere of radius 6 cm?

    • A.17
    • B.6
    • C.8
    • D.16

    Answer: D. 16

    Given 3 cm, 6 cm, asked for How many cones (radius 3 cm, height 6 cm) can be made by melting a sphere of radius 6 cm?. By hence the answer = 16. hence the answer = 16. draw the relevant radii and use the fact that the tangent _|_ radius at the contact point. Putting it together option D) 16. Others fail: option A) '17' is incorrect: Wrong: a step was skipped or HCF/LCM swapped; option B) '6' fails since Wrong: a common multi-step slip gives this.

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