Class 10 · Maths · Trigonometry

Trigonometric ratios of complementary angles MCQs

Practice Trigonometric ratios of complementary angles multiple-choice questions from Trigonometry (Class 10 Maths) - tap an answer for instant feedback and a step-by-step solution. Practice the full set free on the RankByte app.

Trigonometric ratios of complementary anglesQuiz - Solve & Score

  1. Q1. A bridge engineer needs to swap sin 23 deg for the matching ratio of its complement; which value is identical?

    • A.cos 67 deg
    • B.sin 67 deg
    • C.cos 157 deg
    • D.cos 23 deg

    Answer: A. cos 67 deg

    Complementary-angle rule: sin(t) = cos(90 - t). Put t = 23, so sin 23 deg = cos 67 deg.

  2. Q2. Rewriting cos 31 deg through the angle that completes it to a right angle, what equal ratio appears?

    • A.sin 149 deg
    • B.sin 59 deg
    • C.cos 59 deg
    • D.sin 31 deg

    Answer: B. sin 59 deg

    Complementary-angle rule: cos(t) = sin(90 - t). Put t = 31, so cos 31 deg = sin 59 deg.

  3. Q3. To merge two terms a coder substitutes tan 18 deg with the co-ratio of (90 - 18) deg; what does it become?

    • A.tan 72 deg
    • B.cot 162 deg
    • C.cot 18 deg
    • D.cot 72 deg

    Answer: D. cot 72 deg

    Complementary-angle rule: tan(t) = cot(90 - t). Put t = 18, so tan 18 deg = cot 72 deg.

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