pH, hydrolysis, buffers, neutralisation MCQs
Practice pH, hydrolysis, buffers, neutralisation multiple-choice questions from Acids, Bases and Salts (Class 10 Science) - tap an answer for instant feedback and a step-by-step solution. Practice the full set free on the RankByte app.
pH, hydrolysis, buffers, neutralisationQuiz - Solve & Score
Q1. Which of the following pairs forms an acidic salt solution in water?
- A.NH4Cl in water
- B.CH3COONa in water
- C.NaCl in water
- D.K2CO3 in water
Answer: A. NH4Cl in water
Textbook fact: NH4Cl is the salt of strong acid (HCl) + weak base (NH3); NH4+ hydrolyses to give H+, so pH < 7. CH3COONa, K2CO3 are basic salts; NaCl is neutral. Therefore the correct option is A) NH4Cl in water.
Q2. Which is the pH of a 1.0 × 10^-3 M H2SO4 solution (assume both protons ionise completely)?
- A.2.70
- B.3.00
- C.2.00
- D.3.30
Answer: A. 2.70
Data from the problem: 1.0; 10; -3; 2; 4. To find: the unknown asked in the stem. Working tool - [H+] = 2 × 10^-3 M (two protons per molecule). This is the equation that links the given quantities to the unknown (chemistry, chapter 'Acids, Bases and Salts'). Carrying out the arithmetic: [H+] = 2 × 10^-3 M (two protons per molecule) → pH = -log(2 × 10^-3) = 3 - log 2 = 3 - 0.30 = 2.70. The intuition - Trap 3.00 ignores second proton. Putting it together the answer is A) 2.70.
Q3. Which of the following will turn red litmus blue?
- A.Aqueous solution of Na2CO3
- B.Lemon juice
- C.Vinegar
- D.Solution of NH4Cl
Answer: A. Aqueous solution of Na2CO3
NCERT fact (chemistry, chapter 'Acids, Bases and Salts'): Na2CO3 is a salt of strong base + weak acid → aqueous solution is basic (pH > 7), turning red litmus blue. Lemon juice (citric acid), vinegar (acetic acid), NH4Cl (acidic salt) are all acidic. Final answer - A) Aqueous solution of Na2CO3.
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