Resistance and Factors Affecting ResistancePractice Questions & MCQs
Practice Resistance and Factors Affecting Resistance questions from Electricity (Class 10 Science) - important MCQs with answers and step-by-step solutions. Solve the sample questions below, then practice the full set free on the RankByte app.
Resistance and Factors Affecting ResistanceQuiz - Solve & Score
Q1. Which factor does NOT affect the resistance of a given wire?
- A.its length
- B.its temperature
- C.the potential difference applied across it
- D.its cross-sectional area
Answer: C. the potential difference applied across it
The core fact here is - Ohm's law: V = I*R for a resistor at constant temperature, so I = V/R and R = V/I; substitute the given pair into this relation => the unknown reduces to a single value; hence the answer = the potential difference applied across it. That fits the listed correct option directly - Correct. Looking at the others: option A) 'its length' misses the point - Length affects resistance (R ∝ L); option B) 'its temperature' doesn't hold - Temperature affects resistance. Hence the answer is C) the potential difference applied across it.
Q2. Which wire will have the least resistance?
- A.a long, thin nichrome wire
- B.a long, thin copper wire
- C.a short, thin nichrome wire
- D.a short, thick copper wire
Answer: D. a short, thick copper wire
Going back to the NCERT chapter, Ohm's law: V = I*R for a resistor at constant temperature, so I = V/R and R = V/I; substitute the given pair into this relation => the unknown reduces to a single value; hence the answer = a short, thick copper wire. That fits the listed correct option directly - Correct. As for the rest: option A) 'a long, thin nichrome wire' is incorrect: Long, thin and high-resistivity gives the most resistance; option B) 'a long, thin copper wire' doesn't hold - Long and thin gives the most resistance. Hence the answer is D) a short, thick copper wire.
Q3. Which factor increases the resistance of a given metallic wire?
- A.shortening it
- B.increasing its cross-sectional area
- C.cooling it
- D.raising its temperature
Answer: D. raising its temperature
Which principle settles this? Ohm's law: V = I*R for a resistor at constant temperature, so I = V/R and R = V/I; substitute the given pair into this relation => the unknown reduces to a single value; hence the answer = raising its temperature. Does that line up with one of the options? Yes - Correct. And the rest? option A) 'shortening it' doesn't hold - Shorter length lowers resistance; option B) 'increasing its cross-sectional area' doesn't hold - Larger area lowers resistance. Pick: D) raising its temperature.
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