Eye, defects, dispersion, scatteringPractice Questions & MCQs
Practice Eye, defects, dispersion, scattering questions from The Human Eye and the Colourful World (Class 10 Science) - important MCQs with answers and step-by-step solutions. Solve the sample questions below, then practice the full set free on the RankByte app.
Eye, defects, dispersion, scatteringQuiz - Solve & Score
Q1. Why is the colour of the clear sky overhead a brighter blue at high altitudes (e.g., from a mountain top) than at sea level?
- A.Less atmosphere above causes less multiple scattering and absorption, preserving the dominant Rayleigh-scattered blue
- B.Air is colder, so blue is brighter
- C.Sunlight intensity is higher
- D.The pupil dilates at high altitude
Answer: A. Less atmosphere above causes less multiple scattering and absorption, preserving the dominant Rayleigh-scattered blue
NCERT fact (physics, chapter 'The Human Eye and the Colourful World'): At high altitudes, less air column means fewer particles to cause secondary scattering and absorption that would whiten the sky. The Rayleigh-scattered blue dominates more purely, giving deeper blue. Sunlight intensity is similar (slightly higher) but the colour change is from atmospheric path effect. Final answer - A) Less atmosphere above causes less multiple scattering and absorption, preserving the dominant Rayleigh-scattered blue.
Q2. In a primary rainbow, which colour appears on the OUTER edge of the arc?
- A.Green
- B.Red
- C.Violet
- D.Blue
Answer: B. Red
In a primary rainbow light undergoes one internal reflection; red emerges at a larger angle (about 42 deg) than violet (about 40 deg), so red is on the outer edge and violet on the inner.
Q3. Holding a 1 cm pencil at 25 cm (the near point), what angle does a healthy eye perceive it to subtend? (in degrees)?
- A.0.57 deg
- B.2.29 deg
- C.0.040 deg
- D.25.0 deg
Answer: B. 2.29 deg
Angle (rad) = height/distance = 1/25 = 0.040 rad. In degrees: 0.040*180/pi = 2.29 deg.
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