Graphical methods, solutions, applicationsPractice Questions & MCQs
Practice Graphical methods, solutions, applications questions from Linear Equations in Two Variables (Class 9 Maths) - important MCQs with answers and step-by-step solutions. Solve the sample questions below, then practice the full set free on the RankByte app.
Graphical methods, solutions, applicationsQuiz - Solve & Score
Q1. For what value of k does the equation kx + 2y = 5 have (1, 2) as a solution?
- A.1
- B.2
- C.−1
- D.5
Answer: A. 1
Start by listing the data - 2, 5, 1, 2 (math, chapter 'Linear Equations in Two Variables'). What we must find: the requested quantity. The principle that connects these is - k(1) + 2(2) = 5 ⇒ k + 4 = 5 ⇒ k = 1. Substituting and simplifying: k(1) + 2(2) = 5 ⇒ k + 4 = 5 ⇒ k = 1. That lands on option A) 1.
Q2. The point (3, −4) lies on which of these lines?
- A.2x + y = 2
- B.x + y = 1
- C.x − y = 1
- D.3x + 4y = 0
Answer: A. 2x + y = 2
Reading the problem, 3, 4 (math, chapter 'Linear Equations in Two Variables'). Our target: the unknown asked. The principle that connects these is - Check 2x + y at (3,−4): 6 + (−4) = 2. The arithmetic is: Check 2x + y at (3,−4): 6 + (−4) = 2. That lands on option A) 2x + y = 2.
Q3. The line y = 3x − 5 passes through which of the following points?
- A.(2, 1)
- B.(2, 0)
- C.(0, 5)
- D.(1, 3)
Answer: A. (2, 1)
The problem states: 3; 5. We need: the unknown asked in the stem. Formula - Check (2,1): 3(2) − 5 = 1. This is the equation that links the given quantities to the unknown (math, chapter 'Linear Equations in Two Variables'). Numerically: Check (2,1): 3(2) − 5 = 1. What makes this the correct method - ✓ It passes through (2,1). Consequently the answer is A) (2, 1).
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