Class 9 · Maths · Surface Areas and Volumes

Surface Area of a Right Circular Cylinder MCQs

Practice Surface Area of a Right Circular Cylinder multiple-choice questions from Surface Areas and Volumes (Class 9 Maths) - tap an answer for instant feedback and a step-by-step solution. Practice the full set free on the RankByte app.

Surface Area of a Right Circular CylinderQuiz - Solve & Score

  1. Q1. Two cylinders have base radii in the ratio 2:3 and heights in the ratio 5:4. Combining both factors, the ratio of their curved surface areas is?

    • A.5:6
    • B.2:3
    • C.5:4
    • D.20:36

    Answer: A. 5:6

  2. Q2. Two cylinders have base radii in the ratio 1:2 and heights in the ratio 3:5. Combining both factors, the ratio of their curved surface areas is?

    • A.3:10
    • B.1:2
    • C.3:5
    • D.3:20

    Answer: A. 3:10

  3. Q3. Two cylinders have base radii in the ratio 3:4 and heights in the ratio 2:3. Combining both factors, the ratio of their curved surface areas is?

    • A.1:2
    • B.3:4
    • C.2:3
    • D.18:48

    Answer: A. 1:2

    Spot-the-setup - a typical math numerical. The data on the table: 3, 4, 2, 3. We are after the quantity the stem asks for. Tool of choice - CSA ratio = (r1 h1):(r2 h2) = (3×.2):(4×.3) = 6:12 = 1:2. Rearrange it for the unknown before substituting. Numbers in: CSA ratio = (r1 h1):(r2 h2) = (3×.2):(4×.3) = 6:12 = 1:2. Lock in option A) 1:2. Trap-watch: option B) '3:4' is incorrect: CSA depends on both radius and height: 2πrh; option C) '2:3' is incorrect: Height alone is not enough; multiply by the radius ratio too.

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