An ice carver must just melt a 15 g chip of ice that is already sitting at 0 degrees C into water at the same temperature; what heat input does this need?

5010 J. Melting at a constant 0 degrees C: Q = m x Lf = 15 x 334 = 5010 J.

A glass of cola contains 12 g of ice cubes at 0 degrees C that gradually become water at 0 degrees C; what amount of heat do the cubes draw from the drink?

4008 J. Melting at a constant 0 degrees C: Q = m x Lf = 12 x 334 = 4008 J.

A laboratory demonstration converts 50 g of finely crushed ice at 0 degrees C entirely to water at 0 degrees C; how much energy must be supplied?

16700 J. Melting at a constant 0 degrees C: Q = m x Lf = 50 x 334 = 16700 J.

Class 9 · Science · Chemistry

Matter in Our Surroundings MCQs

Take an interactive Matter in Our Surroundings quiz for Class 9 Science - tap an answer for instant feedback and a step-by-step solution. These are a few sample questions; practice the full Matter in Our Surroundings set free on the RankByte app.

Topics covered

Characteristics of Particles of MatterStates of Matter (Solid, Liquid, Gas)Change of State (Melting, Boiling, Sublimation)Evaporation and Cooling EffectLatent Heat of Fusion and VaporisationStates, changes, latent heat, evaporation, factors

Practice Matter in Our Surroundings by topic

Focused MCQ quizzes for each topic.

Change of State (Melting, Boiling, Sublimation)Characteristics of Particles of Matter Evaporation and Cooling Effect Latent Heat of Fusion and Vaporisation States of Matter (Solid, Liquid, Gas)States, changes, latent heat, evaporation, factors

Matter in Our SurroundingsQuiz - Solve & Score

A few sample questions with instant answers and solutions - the full set is in the app.

Q1. An ice carver must just melt a 15 g chip of ice that is already sitting at 0 degrees C into water at the same temperature; what heat input does this need?
- A.33900 J
- B.63 J
- C.5010 J
- D.334 J
Answer: C. 5010 J
Melting at a constant 0 degrees C: Q = m x Lf = 15 x 334 = 5010 J.
Q2. A glass of cola contains 12 g of ice cubes at 0 degrees C that gradually become water at 0 degrees C; what amount of heat do the cubes draw from the drink?
- A.334 J
- B.4008 J
- C.50.4 J
- D.27120 J
Answer: B. 4008 J
Melting at a constant 0 degrees C: Q = m x Lf = 12 x 334 = 4008 J.
Q3. A laboratory demonstration converts 50 g of finely crushed ice at 0 degrees C entirely to water at 0 degrees C; how much energy must be supplied?
- A.16700 J
- B.334 J
- C.113000 J
- D.210 J
Answer: A. 16700 J
Melting at a constant 0 degrees C: Q = m x Lf = 50 x 334 = 16700 J.